7t^2+3300t-3000=0

Solution for 7t^2+3300t-3000=0 equation:

7t^2+3300t-3000=0

a = 7; b = 3300; c = -3000;
Δ = b2-4ac
Δ = 33002-4·7·(-3000)
Δ = 10974000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10974000}=\sqrt{400*27435}=\sqrt{400}*\sqrt{27435}=20\sqrt{27435}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3300)-20\sqrt{27435}}{2*7}=\frac{-3300-20\sqrt{27435}}{14}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3300)+20\sqrt{27435}}{2*7}=\frac{-3300+20\sqrt{27435}}{14}
$